| As well all know the value of pii is a number with the | | | | power of 3 |
| infinite desimals. Euclidean geometric formulas which | | | | Resolving the numerical value of pii is as |
| includes the value of pii, for example, if we consider | | | | follows: |
| the formula of circle 2 x (pii) x (r). This equation by | | | | pii = ((3)x(V))/((4)x(r) to |
| calculations do not ever give the circle arcending as | | | | power of 3)) |
| always read the value of calculating the lenght of the | | | | 7. Since V = (8m2))/(roo)) so |
| ring must be taken pii the value of many decimals. | | | | pii = ((3)x(m2)/(roo))/((4)x(r) |
| For example, the exact value of 3 m radius of | | | | to power of 3)) |
| curvature of circular arc is 2 x (pii) x (r) = 6 x (pii) m. | | | | where, |
| Even then, an infinite value of pii has to be the not | | | | m2 = mass of water at |
| endles value of decimals. I have wondered how to | | | | temperature of + 20C-degrees (kg) |
| figure the value of pii can be calculated exactly. The | | | | roo = density of water at the |
| method is as follows: | | | | temperature of +20C-degrees, is 1000 kg/m3 |
| 1. Preparing a very detailed glass ball with an inside | | | | r = internal radius of |
| diameter D of 1 m. It is recalled that in Paris | | | | the glass ball (m) |
| maintaining a certain kind of metal bar that is | | | | D = inside diameter of |
| manufactured calibration of the length of 1 m. | | | | the glass ball (m) |
| 2. Weighting the glass ball mass of m1 (kg). | | | | So resulting the value of pii to be used |
| 3. Filling the glass ball by +20 C-degrees water | | | | internationally: |
| (density is 1000 kg/m3). | | | | pii = ((3)x(10 to power |
| 4. Weighting this mass of glass ball and the mass of | | | | of -3))/((4)x(D/2) to power of 3)) |
| water inside the glass ball, m3 (kg). | | | | Circumtances of pii determination shall be such that |
| 5. Dismissing this mass of glass ball ie. the mass m3 | | | | the laboratory T = +20C-degrees, glass ball T = |
| - m1 = m2 (kg). | | | | +20C-degrees and water T = +20C-degrees. By the |
| 6. Calculating the volume (V) by formula in glass ball | | | | method explained above we will get as exact value |
| as follows: | | | | to be used in Euclidean geometry and in many |
| V = ((4/3))x(pii)x(r) to | | | | other mathematical formulas. |